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Hagrid
The area of the triangle is 75.99 units squared or approximately 76 units squared.

An Isosceles Triangle is a triangle with two congruent sides and two congruent angles. One side of the triangle measures 10 units, which is the base. The other two sides measures 16 units. The perimeter of the triangle is 10 + 16 + 16 = 42 units.

To get the area of a triangle, we use the formula
[tex]A = \frac{1}{2} bh[/tex]

The height or altitude of the triangle can be calculated from Pythagorean theorem, which is equal to [tex] \sqrt{231} [/tex] units.

Substituting values into the formula for the area of a triangle, we get
[tex]A = \frac{1}{2} (10)( \sqrt{231} ) \\ A =75.99 units squared \\ [/tex]

The answer can be rounded of into 76 units squared.
boffeemadrid

The area of the given triangle is required.

The area of the triangle is [tex]75.99\ \text{units}^2[/tex]

Triangles

One side of the triangle measures 10 units

The perimeter of the triangle is 42 units

Let us assume the base of the triangle is 10 units.

Let [tex]x[/tex] be the length of the sides that are equal in length

[tex]x+x+10=42\\\Rightarrow x=\dfrac{42-10}{2}\\\Rightarrow x=16\ \text{units}[/tex]

The height of the triangle is

[tex]h=\sqrt{16^2-5^2}=\sqrt{231}\ \text{units}[/tex]

The area of a triangle is given by

[tex]A=\dfrac{1}{2}bh\\\Rightarrow A=\dfrac{1}{2}\times10\times\sqrt{231}\\\Rightarrow A=5\sqrt{231}=75.99\ \text{units}^2[/tex]

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