Answer:
1.8 x 10^ 24 atoms of oxygen
Explanation:
The molecular weight of ozone is known to be 48 grams / mol. Here we are given a sample of 48 grams of ozone as well, so in 48 grams of ozone the number of moles = 48 / 48 = 1,
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1 mole of ozone is equal to 6.0221415 × 10^23 molecules of ozone. Respectively, 1 molecule of ozone has 3 atoms of oxygen. Thus, you can conclude the following -
3 * 6.0221415 × 10^23 = ( About ) 1.8 x 10^ 24 atoms of oxygen
Hope that helps!
The volume of 48 grams of ozone at room temperature and pressure (r.t.p) is equal to 24 [tex]dm^3[/tex].
Given the following data:
Scientific data:
To determine the volume of 48 grams of ozone at room temperature and pressure (r.t.p):
First of all, we would calculate the number of moles of ozone contained in 48 grams of ozone by using the formula:
[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{48}{48}[/tex]
Number of moles = 1.0 moles
By stoichiometry:
1 mole of ozone = 24 [tex]dm^3[/tex]
Note: At room temperature and pressure (r.t.p), the volume of any gas is equal to 24 [tex]dm^3[/tex] or 24,000 [tex]cm^3[/tex].
In conclusion, the volume of 48 grams of ozone at room temperature and pressure (r.t.p) is equal to 24 [tex]dm^3[/tex].
Read more on moles here: Read more: https://brainly.com/question/16906167
