Answer:
Net force = 21.12 N
angle for the force α = 45°
Explanation:
In this problem, we will take the left as the negative x-axis, the right as the positive x-axis, and the upward direction as the positive y-axis.
The 20 N force to the left has an x component of -20 N, and y component of 0 N
The 35 N force to the right has a x component of 35 N, and a y component of 0 N
The 15 N upwards has an x component of 0 N, and a y component of 15 N
We resolve the forces into the x and y components.
for the x component Fx
Fx = -20 + 35 + 0 = 15 N
For the y component Fy
Fy = 0 + 0 + 15 = 15 N
Net force Fn = [tex]\sqrt{Fx^{2} + Fy^{2} }[/tex]
[tex]Fn = \sqrt{(15)^{2} + (15^{2} ) }[/tex]
Net force Fn = 21.21 N
for the angle,
[tex]tan\alpha = \frac{Fy}{Fx} = \frac{15}{15}[/tex]
[tex]tan\alpha = 1[/tex]
α = [tex]tan^{-1}[/tex] 1
angle for force α = 45°
