Answer:
Height of building is 57.12 m.
Step-by-step explanation:
Let us try to understand the given dimensions as per the attached diagram.
Please refer to attached image (Right angled [tex]\triangle OBT[/tex])
with [tex]\angle B =90^\circ[/tex]
Let O be the point where the Surveyor is standing.
B be the point of the base of building.
T be the point of top of building.
As per question statement,
[tex]\angle O = 55^\circ[/tex]
Side OB = 40 m
To find: Side BT = ?
Using tangent trigonometric identity:
[tex]tan\theta =\dfrac{Perpendicular}{Base}[/tex]
[tex]tanO =\dfrac{BT}{BO}\\\Rightarrow tan55^\circ = \dfrac{BT}{40}\\\Rightarrow BT = tan55^\circ \times 40\\\Rightarrow BT = 1.43\times 40\\\Rightarrow BT = 57.12 m[/tex]
So, height of building is 57.12 m.
