Answer:
The maximum height the projectile reaches is 100 feet
Step-by-step explanation:
Notice that the given equation representing the height of the projectile is a quadratic equation which negative leading coefficient (-16). Such type of equations would have a parabola that branches downwards as its graph.
therefore, what we need to find is the coordinates of the top vertex of that parabola. We can use for such the typical formula for the x-position of the vertex of a parabola with standard equation:
[tex]f(x)=ax^2+bx+c[/tex]
with x-position of the vertex given by:
[tex]x_v=\frac{-b}{2a}[/tex]
Then in our case ([tex]H(t)=-16t^2+16t+96[/tex]) we have:
Horizontal position of the vertex given by:
[tex]t_{vertex}=\frac{-16}{2(-16)} =\frac{1}{2}[/tex]
and now we can find the maximum height plugging this value into the height expression:
[tex]H(t)=-16(\frac{1}{2}) ^2+16\,(\frac{1}{2})+96=-4+8+96=100\,\,ft[/tex]
