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How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?


1) 17.5ml


2) 35ml


3) 52.5ml


4) 3.0ml

Respuesta :

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

[tex]H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O[/tex]

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

[tex]2*n_{acid}=n_{base}[/tex]

And in terms of concentrations and volumes:

[tex]2*M_{acid}V_{acid}=M_{base}V_{base}[/tex]

Thus, we solve for the volume of acid:

[tex]V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL[/tex]

Best regards.