Answer:
1) 17.5 mL
Explanation:
Hello,
In this case, the reaction between sulfuric acid and potassium hydroxide is:
[tex]H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O[/tex]
In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:
[tex]2*n_{acid}=n_{base}[/tex]
And in terms of concentrations and volumes:
[tex]2*M_{acid}V_{acid}=M_{base}V_{base}[/tex]
Thus, we solve for the volume of acid:
[tex]V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL[/tex]
Best regards.