Answer:
[tex]CosB = \frac{48}{80}[/tex]
Step-by-step explanation:
Given
AB = 48, AC = 64, and BC = 80
Required
Determine the ratio of cosB
The first step is to determine, which type of triangle it is.
Checking for Right Angled Triangle
For a triangle to be a right angled triangle, the square of the largest side must be equal to the sum of squares of other sides
This implies that:
[tex]80^2 = 48^2 + 64^2[/tex]
[tex]6400 = 2304 + 4096[/tex]
[tex]6400 = 6400[/tex]
Hence, the triangle is a right angled triangle [See attachment]
From trigonometry;
[tex]CosB = \frac{Adjacent}{Hypotenuse}[/tex]
The adjacent of B = 48 while the hypotenuse is 80;
Hence;
[tex]CosB = \frac{48}{80}[/tex]
Hence, the ratio of cos B is [tex]CosB = \frac{48}{80}[/tex]
