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g 12. Spring A has a spring constant of 100 N/m and spring B has a spring constant of 200 N/m, and both have the same displacement of 0.20 m. The spring potential energy of spring A is _____ that of spring B. twice half the same as None of the above

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abidemiokin

Answer:

A. twice

Explanation:

Spring potential Energy is expressed as E = 1/2 ke²

k = spring constant

e = displacement of the string

If  Spring A has a spring constant of 100 N/m and displacement of 0.2m, the spring potential energy will be;

= 1/2 * 100 * 0.2²

= 50 * 0.04

= 2Joules

If spring B has a spring constant of 200 N/m and displacement of 20m, the spring potential energy will be;

= 1/2 * 200 * 0.2²

= 100 * 0.04

= 4Joules

From the values gotten, it can be seen that the spring potential energy of spring B is twice that of A

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