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Consider the following reversible reaction. Upper C upper O (g) plus 2 upper H subscript 2 (g) double-headed arrow upper C upper H subscript 3 upper O upper H (g). What is the equilibrium constant expression for the given system?

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Answer:

Answer:K subscript e q equals StartFraction StartBracket upper C upper O subscript 2 EndBracket StartBracket upper C a upper O EndBracket over StartBracket upper C a upper C upper O subscript 3 EndBracket EndFraction

Explanation: the answer has it's root in Law of mass action which states that; the rate of a chemical reaction is directly proportional to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

Lanuel

The equilibrium constant expression for the given system of reaction is [tex]K_c = \frac{ [CH_3OH]}{ [CO][H_2]^2}[/tex]

What is an equilibrium constant?

An equilibrium constant can be defined as an expression that shows the relationship between the reactants and products of a chemical reaction that is at equilibrium with respect to a specific unit.

Mathematically, the equilibrium constant is given by this formula:

[tex]K_c = \frac{ [C]^c[D]^d}{ [A]^a[B]^b}[/tex]

Where:

  • A, B is the product.
  • C, D is the reactant.

How to determine equilibrium constant.

First of all, we would write the properly balanced chemical equation with the phase for this system of chemical reaction:

                         CO(g) + 2H₂(g) ⇆ CH₃OH(g)  

Substituting the parameters into the formula, we have;

[tex]K_c = \frac{ [CH_3OH]}{ [CO][H_2]^2}[/tex]

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