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A model rocket is launched from ground level. Its height, h meters above the ground, is a function of time t seconds after launch and is given by the equation h=-4.9t^2+68.6t What would be the

maximum height, to the nearest meter, attained by the model?

Respuesta :

Answer:

240 m to nearest meter.

Step-by-step explanation:

h = -4.9t^2 + 68.6t

We need to convert this to vertex form to find the maximum value of h:

h = -4.9(t^2 - 14t)

h = -4.9[(t - 7)^2 - 49]

h =  -4.9(t - 7)^2 + 240.1

So maximum height is when t = 7 and it's 240.1 meters.

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