Answer:
[tex]V_2 = 150\ mmHg[/tex]
Explanation:
Given
Initial Pressure = 300 mmHg
Initial Volume = 380 L
Required
Volume of the gas at standard pressure
This can be solved using Boyle's law;
Which states that [tex]P_1V_1 = P_2V_2[/tex]
Where
[tex]P_1 = Initial\ Pressure = 300\ mmHg\\P_2 = Standard\ Pressure = 760\ mmHg\\V_1 = Initial\ Volume = 380L\\V_2 = Final\ Volume = ?[/tex]
Substitute the above values in the Boyle's law equation
[tex]P_1V_1 = P_2V_2[/tex] becomes
[tex]300 * 380 = 760 * V_2[/tex]
[tex]114000 = 760V_2[/tex]
Divide both sided by 760
[tex]\frac{114000}{760} = \frac{760V_2}{760}[/tex]
[tex]\frac{114000}{760} = V_2[/tex]
[tex]150 = V_2[/tex]
[tex]V_2 = 150\ mmHg[/tex]
Hence, the volume of the gas as standard pressure is 150 mmHg
