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A physicist wants to study the motion of a car.

a. The physicist measures how long it takes a car to go 50 miles. How many
kilometers is this? (Note: 1 mi = 1.61 km)

b. In another experiment, the car travels 22.3 miles. How many yards is this?
(Note: 1 mi = 5280 ft; 1 yd = 3 ft)

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Answer:

a.

Explanation:

in a

[tex]1 mi = 1.61km[/tex]

so,in 50 miles

[tex]50 mi = 50 \times 1.61[/tex]

[tex] = 80.5 \: km[/tex]

in b

[tex]1 \: mi = 1760 \: yd[/tex]

so in 22.3 miles

[tex]22.3 = 22.3 \times 1760[/tex]

[tex] = 39248 \: yd[/tex]

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