You are trying to overhear a juicy conversation, but from your distance of 20.0 m, it sounds like only an average whisper of 20.0 dB. So you decide to move closer to give the conversation a sound level of 70.0 dB instead. How close should you come?

Respuesta :

Given that,

Distance = 20.0 m

Average whisper = 20.0 dB

Sound level = 70.0 dB

We know that,

The minimum intensity is

[tex]I_{o}=10^{-12}\ W/m^2[/tex]

We need to calculate the sound intensity in the distance of 20 m

Using formula of sound intensity

[tex]dB=10\log(\dfrac{I_{a}}{I_{o}})[/tex]

Put the value into the formula

[tex]20=10\log(\dfrac{I_{a}}{10^{-12}})[/tex]

[tex]10^{2}=\dfrac{I_{a}}{10^{-12}}[/tex]

[tex]I_{a}=10^{-10}\ W/m^2[/tex]

If the conversation a sound level of 70.0 dB instead

We need to calculate the sound intensity

Using formula of sound intensity

[tex]dB=10\log(\dfrac{I_{b}}{I_{o}})[/tex]

Put the value into the formula

[tex]70=10\log(\dfrac{I_{a}}{10^{-12}})[/tex]

[tex]10^{7}=\dfrac{I_{b}}{10^{-12}}[/tex]

[tex]I_{b}=10^{-5}\ W/m^2[/tex]

We know that,

The intensity is inversely proportional with the square of the distance.

We need to calculate the distance

Using formula of intensity

[tex]\dfrac{I_{a}}{I_{b}}=\dfrac{R_{b}^2}{R_{a}^2}[/tex]

Put the value into the formula

[tex]\dfrac{10^{-10}}{10^{-5}}=\dfrac{R_{b}^2}{20^2}[/tex]

[tex]R_{b}^2=20^2\times\dfrac{10^{-10}}{10^{-5}}[/tex]

[tex]R_{b}=\sqrt{20^2\times\dfrac{10^{-10}}{10^{-5}}}[/tex]

[tex]R_{b}=0.063\ m[/tex]

Hence, The distance from the conversation should be 0.063 m.

The distance you should move to achieve a loudness of 70 dB is; 0.0633 m

We are given;

Average distance 1; R_1 = 20 m

Average whisper 1; dB1 = 20 dB

Average whisper 2; dB2 = 70 dB

Now, the formula for loudness in dB is;

dB = 10log(I/I_o)

Where;

I is the intensity of the sound

I_o is the minimum intensity that a human ear can detect = 10^(-12) W/m²

  • Thus, for dB1 = 20 dB;

20 = 10log (I/10^(-12))

20/10 = log (I/10^(-12))

log (I/10^(-12)) = 2

10² = (I/10^(-12))

I = 10² × 10^(-12)

I_1 = 10^(-10) W/m²

  • Similarly, for dB2 = 70 dB;

70 = 10log (I/10^(-12))

70/10 = log (I/10^(-12))

log (I/10^(-12)) = 7

10^(7) = (I/10^(-12))

I = 10^(7) × 10^(-12)

I_2 = 10^(-5) W/m²

The relationship between their intensities and distance is;

I_1/I_2 = (R_2/R_1)²

Where R_2 is the distance you should move to achieve a loudness of 70 dB.

Thus;

(10^(-10))/(10^(-5)) = R_2/20

(R_2)/20 = √(10^(-5))

(R_2)/20 = 0.00316227766

R_2 = 20 × 0.00316227766

R_2 = 0.0632 m

Read more at; https://brainly.com/question/21195959