A firework is initially at rest explodes into 2 pieces one of which weighing 2.0 kg flies to the right at15 m/s the other piece flies to tje left at 20m/s wjat is tge mass of firework before explosion??

Respuesta :

Answer:

3.5 kg

Explanation:

Momentum is conserved.

Mu = m₁v₁ + m₂v₂

0 = (2.0 kg) (15 m/s) + m (-20 m/s)

m = 1.5 kg

M = m + 2.0 kg

M = 3.5 kg

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Answer:

3.5 kg

Explanation:

use the equation; (m1v1i) + (m2v2i) = (m1v1f) + (m2v2f)

= m1(0) - m1v1f = m2v2f - m2(0)

= (-2.0)(15)/-20

= 1.5 kg

then add the other piece (2.0kg)

1.5 + 2.0 = 3.5 kg