Answer:
[tex]x=20[/tex]
[tex]y=10\,\sqrt{3}[/tex]
Step-by-step explanation:
In the triangle we have the following trigonometric equations:
[tex]tan(60^o)=\frac{opposite}{adjacent} \\\sqrt{3} =\frac{y}{10} \\y=10\,\sqrt{3}[/tex]
and also:
[tex]cos(60^o)=\frac{adjacent}{hypotenuse}\\\frac{1}{2} =\frac{10}{x}\\x=20[/tex]