Answer:
[tex]\large \boxed{\sf \begin{aligned}9567&\\+1085&\\----&-\\10652&\\\end{aligned}}[/tex]
Step-by-step explanation:
Hello, let's do it step by step and see what we can find.
[tex]\begin{aligned}\text{ SEND}&\\+\text{ MORE}&\\-----&-\\\text{ MONEY}&\\\end{aligned}[/tex]
We assume that M is different from 0, otherwise we could find several different solutions I would think.
It means that S + M is greater than 10, otherwise the number of digit of the result would have been 4 and not 5.
The only possible number for M is then 1. M = 1
[tex]\begin{aligned}\text{ SEND}&\\+\text{ \boxed{1}ORE}&\\-----&-\\\text{ \boxed{1}ONEY}&\\\end{aligned}[/tex]
But then, S can only by 9, otherwise S + 1 < 10. S = 9
S + 1 = 10 + O if there is no carry over, so S = 9 + O
1 + S + 1 = 10 + O if there is a carry, so S = 8 + O
So O = 0 or O = 1. Wait !? M is already equal to 1 so O must be 0
E cannot be equal to N so 1 + E = N, meaning that there must be a carry over from column second from the right.
and E < 9 as we know that there is no carry over from column 3 from the right.
N + R = 10 + E => 1 + E + R = 10 + E => R = 9, impossible, as S=9
or 1 + N + R = 10 + E => 1 + 1 + E + R = 10 + E => R = 8
And there is a carry over from the column 1 from the right, so:
Y cannot be 0 or 1, as already used so D + E > 11
8 and 9 are already taken so we could have 7 + 5 = 12, 7 + 6 = 13 and that's it.
It means that E is 7 or D is 7.
If E is 7 then E+1=9=N, impossible, so D = 7
Then, E is 5 or 6
if E = 6 E + 1 = N = 7, impossible, so E = 5 and N = 6.
And 7 + 5 = 12 so Y = 2.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
