Respuesta :
Answer:
Reject the null hypothesis that there is no difference between males and females on the recognition task.
Step-by-step explanation:
Use MS-Excel to compute the required values.
Consider the data for male subjects first:
- Mean = [tex]\frac{1}{20}\sum X_{m}}=5.85[/tex]
- SD = [tex]\sqrt{\frac{1}{20-1}\sum (X_{m}-\bar X_{m})^{2}}=1.69[/tex]
- SEM = [tex]\frac{SD}{\sqrt{20}}=0.38[/tex]
Consider the data for female subjects:
- Mean = [tex]\frac{1}{20}\sum X_{f}}=8.15[/tex]
- SD = [tex]\sqrt{\frac{1}{20-1}\sum (X_{f}-\bar X_{f})^{2}}=0.93[/tex]
- SEM = [tex]\frac{SD}{\sqrt{20}}=0.21[/tex]
Use the Data Analysis tool in Excel to perform the hypothesis test.
The hypothesis can be defined as follows:
H₀: There is no difference between the two responses, i.e.[tex]\mu_{m}-\mu_{f}=0[/tex] .
Hₐ: There is a significant difference between the two responses, i.e.[tex]\mu_{m}-\mu_{f}\neq 0[/tex] .
Consider the Excel output for the hypothesis test.
The test statistic value is:
t = -5.32
The degrees of freedom is:
df = 38
The p value associated with the t value is:
p-value = 4.91025E-06 < 0.05
As the p-value is less than the significance level the null hypothesis will be rejected.
Conclusion:
Reject the null hypothesis that there is no difference between males and females on the recognition task.