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a man pulls a box with a force of 90.0 N directed along the handle which makes angle of 45 degrees with the ground. find the horizontal and vertical components of this force

Respuesta :

onyebuchinnaji

Answer:

The horizontal component of the force, Fₓ = 63.64 N

The vertical component of the force, [tex]F_y[/tex] =  63.64 N

Explanation:

Given;

magnitude of the force, F = 90 N

angle between the handle and the ground, θ = 45°

The horizontal component of the force, Fₓ = Fcosθ

Fₓ = 90 x cos45

Fₓ = 63.64 N

The vertical component of the force, [tex]F_y = Fsin \theta[/tex]

[tex]F_y[/tex] = 90 sin45

[tex]F_y[/tex] = 63.64 N

Therefore, the horizontal  and vertical components of the force is 63.64 N.

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