Respuesta :
Answer:
The number of hydrogen atoms in 36.04 g sample of steam is 2.408 × 10²⁴ atoms of hydrogen
Explanation:
The given parameters are;
The mass of the sample of water, H₂O = 36.04 g
From the principle of conservation of matter, the mass of the water = The mass of the steam, therefore;
The mass of the steam = 36.04 g
The molar mass of H₂O = 18.01528 g/mol
Therefore, the number of moles, n, of H₂O in the 36.04 g of steam is given as follows;
n = Mass/(Molar Mass) = (36.04 g)/(18.01528 g/mol) = 2.00052399963 ≈ 2 moles
The number of molecules of H₂O per mole of H₂O is geven by the Avogadro's number = 6.02 × 10²³ molecules
Therefore;
The number of H₂O in 2 moles of H₂O = 2 × 6.02 × 10²³ = 1.204 × 10²⁴ molecules
The number of hydrogen atoms per molecule of H₂O = 2 hydrogen atoms
Therefore;
The number of hydrogen atoms in the 1.204 × 10²⁴ molecules of H₂O = 2 × 1.204 × 10²⁴ molecules of H₂O
Which gives;
The number of hydrogen atoms in the 1.204 × 10²⁴ molecules of H₂O = 2.408 × 10²⁴ atoms of hydrogen
Therefore;
The number of hydrogen atoms in 36.04 g sample of steam = 2.408 × 10²⁴ atoms of hydrogen.
