Complete Question: You are building a shelf that fits in a corner in the figure the entire shelf is XYZ each unit in the coordinate plane represents one inch find the area of the shelf.
Answer:
112.5 units²
Step-by-step explanation:
Area of the shelf = ½*base*height.
The base is the distance between Z(0, 5) and Y(15, 5)
The height is the distance between X(15, 20) and Y(15, 5).
Therefore area of the shelf = ½*ZY*XY
Use the distance formula to find ZY and XY.
Distance between Z(0, 5) and Y(15, 5):
[tex] ZY = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Let,
[tex] Z(0, 5) = (x_1, y_1) [/tex]
[tex] Y(15, 5) = (x_2, y_2) [/tex]
[tex] ZY = \sqrt{(15 - 0)^2 + (5 - 5)^2} [/tex]
[tex] AB = \sqrt{(15)^2 + (0)^2} [/tex]
[tex] AB = \sqrt{225 + 0} = \sqrt{225} [/tex]
[tex] AB = 15 [/tex]
Distance between X(15, 20) and Y(15, 5):
[tex] XY = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Let,
[tex] X(15, 20) = (x_1, y_1) [/tex]
[tex] Y(15, 5) = (x_2, y_2) [/tex]
[tex] XY = \sqrt{(15 - 15)^2 + (5 - 20)^2} [/tex]
[tex] XY = \sqrt{(0)^2 + (-15)^2} [/tex]
[tex] XY = \sqrt{0 + 225} = \sqrt{225} [/tex]
[tex] XY = 15 [/tex]
Area of shelf = ½*15*15 = ½*225 = 112.5 units²
