Answer :
[tex]Al(OH)_3(aq)+K_3PO_3(aq)\rightarrow AlPO_3(s)+3KOH(aq)[/tex]
[tex]Al^{3+}(aq)+3OH^{-}(aq)+3K^{+}(aq)+PO_3^{3-}(aq)\rightarrow AlPO_3(s)+2K^+(aq)+3OH^{-}(aq)[/tex]
[tex]Al^{3+}(aq)+PO_3^{3-}(aq)\rightarrow AlPO_3(s)[/tex]
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The complete balanced equation will be,
[tex]Al(OH)_3(aq)+K_3PO_3(aq)\rightarrow AlPO_3(s)+3KOH(aq)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]Al^{3+}(aq)+3OH^{-}(aq)+3K^{+}(aq)+PO_3^{3-}(aq)\rightarrow AlPO_3(s)+2K^+(aq)+3OH^{-}(aq)[/tex]
In this equation, [tex]K^+\text{ and }OH^-[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]Al^{3+}(aq)+PO_3^{3-}(aq)\rightarrow AlPO_3(s)[/tex]