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20. What will be the concentration, in mol dm, of the resulting solution when 200 cm' of
0.200 mol dmhydrochloric acid, HCl(aq) are mixed with 300 cm of 0.100
mol dm HCl(aq)?

Respuesta :

ChoiSungHyun

Answer:

0.140mol/dm^3.

Explanation:

200cm3 = 0.2dm^3.

0.2dm^3 * 0.200mol/dm^3 = 0.040mol

300cm^3 = 0.3dm^3

0.3dm^3 * 0.100mol/dm^3 = 0.030mol

The number of moles is 0.070mol of HCl (aq).

The volume of the solution is 0.5dm^3.

Hence the concentration is 0.140mol/dm^3.

The concentration is 0.140mol/dm³.

What is concentration?

  • The concentration of solution is the amount of solute that are dissolved in solution.
  • The concentration can be measured by dividing the weight of solute in grams to the volume of solution.

200cm³ = 0.2dm³

0.2dm³ x 0.200mol/dm³= 0.040mol

300cm³ = 0.3dm³

0.3dm³ x 0.100mol/dm³ = 0.030mol

The number of moles is 0.070mol of HCl

The volume of the solution is 0.5dm³

Concentration = Number of moles/volume in dm³

                        = 0.070mol/0.5dm³

                        = 0.140mol/dm³

Hence, the concentration is 0.140mol/dm³

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