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soniyarobinson45

Answer: By definition, that means there are two integers a and b with no common divisors where: a/b = square root of 6. ... Then our initial assumption must be false, so the square root of 6 cannot be rational. There you have it: a rational proof of irrationality.

√49 = 7, and so it's a rational number. In fact, this number is an integer. (Not every radical is irrational.)

rococo908

Answer:

Square root of 6

Step-by-step explanation:

The square root of 6 is an irrational number because 6 is not a perfect square.

Meanwhile, the square root of 49 is 7, which is not irrational, because 49 is a perfect square.

So, the square root of 6 is an irrational number.

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