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A cashier has a total of 30 bills, consisting entirely of $1 bills, $5 bills, and $20 bills. The total dollar amount of these bills is $351. There are nine more $20 bills that $1 bills. How many of each bill denomination are there?

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Answer:

Five= 9 One= 6 Twenty= 15

Step-by-step explanation:

A cashier has a total of 30 bills, made up of ones, fives, and twenties.

o+f+t=30,

The number of twenties is 9 more than the number of ones.

t=9+o,

The total value of the money is $351.

o+5f+20t=351

so we have

o+f+t=30, t=9+o,

o+5f+20t=351

f = 9, o = 6, t = 15

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