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What volume (in mL) of a 0.150 M HNO3 solution will completely react with 35.7 mL of a 0.108 M Na2CO3 solution according to the following balanced chemical equation?

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

In the reaction in Part A, what mass (in grams) of carbon dioxide forms?

Respuesta :

Answer:

Explanation:

where are the anwser choices

CroftersJelly

Answer:

First part: volume of HNO3 solution = 51.4 mL

Second part: mass of CO2 = 0.170 g

Explanation:

First part:

Based on the volume and concentration of the  Na2CO3  solution, there is 3.86  mmol  of  Na2CO3  available to react with  HNO3 . Considering the stoichiometric relationship, you then calculate the volume of a 0.150  M  solution that contains 7.71  mmol  of  HNO3 .

51.4 mL

Second part:

Since the reactant and product have a stoichiometric relationship that is 1:1, 0.00386  mol  of  Na2CO3  can react to form 0.00386  mol  of  CO2 . The molar mass of  CO2  (44.01  g/mol ) is then used to convert the moles to the corresponding mass in grams.

0.170 g

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