Answer:
-1 and -5
Step-by-step explanation:
You must account for negative u values (which the abs nullifies).
So [tex]5u+15=10[/tex] and [tex]5u+15=-10[/tex] is what we have to solve for.
As for usual equations, isolate the u variable.
5u + 15 = 10
5u + 15 (-15) = 10 (-15)
5u = -5
[tex]\frac{5u}{5}=\frac{-5}{1}[/tex]
u = -1
Now you can do the same operation for the other equation and you should get u = -5.
Let's make sure we did it right by replacing u with one of our solutions (-1 or -5).
[tex]|5(-1)+15| = 10\\10 = 10[/tex]
That's true. What about the other one?
[tex]|5(-5)+15|=10\\10=10[/tex]
