Respuesta :
Answer:
Step-by-step explanation:
Mr. Schwartz begins with total number of wheels = 85
he has to order more wheels once he left with less than 40 wheels
so min. no. of wheels he can use before ordering more wheels = 85-40 = 45
Mr. Schwartz uses 4 wheels to build 1 car
Mr. Schwartz uses 45 wheels to build 45÷4 = 11.25 cars
then, if he builds 12 cars then he needs 12×4 = 48 wheels
total supply of wheels he begins with = 85
wheels he used to build 12 cars = 48
so total number of wheels remaining are = 85-48 = 37
since 37 is less than 40 so after building 12 cars Mr. Schwartz need to order more wheels.
Linear inequality that is used to find number of cars before Mr. Schwartz places an order for more wheels is equals to 4x ≥ 45.
What is linear inequality?
"Linear inequality is defined as a expression where we compare two different linear expression with the help of sign of inequality."
According to the question,
Number of supply wheels =85
Number of wheels required for each car = 4
Mr. Schwartz has to order more wheels when,
Number of wheels < 40
x represents number of cars
As per conditions given ,
Inequality used to find number of cars before placing order for more wheels is 80 -40= 45
Therefore, required linear inequality is
4x ≥ 45
Hence, required linear inequality is 4x ≥ 45.
Learn more about linear inequality here
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