When solving a problem it is important to identify your given and needed units, but it is also important to understand the relationship between those units so you will know how to set up your equation in order to solve the problem. Review the data sets below and use the steps of the problem-solving method to determine whether the given measurements would be appropriate for calculating mass, volume, or density.

a. 432 g of table salt occupies 20.0 cm^3 of space
b. 5.00 g 0T balsa wood, density of balsa wood : 0.16 g/cm^3
c. 32 cm^3 sample of gold density of gold 19.3 =g/cm^3
d. 150 g of iron, density of Iron = 79.0 g/cm^3

Question

02-10-2020
Chemistry

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When solving a problem it is important to identify your given and needed units, but it is also important to understand the relationship between those units so you will know how to set up your equation in order to solve the problem. Review the data sets below and use the steps of the problem-solving method to determine whether the given measurements would be appropriate for calculating mass, volume, or density.

a. 432 g of table salt occupies 20.0 cm^3 of space
b. 5.00 g 0T balsa wood, density of balsa wood : 0.16 g/cm^3
c. 32 cm^3 sample of gold density of gold 19.3 =g/cm^3
d. 150 g of iron, density of Iron = 79.0 g/cm^3

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MrRoyal MrRoyal · Answer 1 · 2020-10-02T16:37:39+02:00

Answer:

See Explanation

Explanation:

Given

(a) to (d)

Required

Determine whether the given parameters can calculate the required parameter

To calculate either Density, Mass or Volume, we have

[tex]Density = \frac{Mass}{Volume}[/tex]

[tex]Mass = Density * Volume[/tex]

[tex]Volume = \frac{Mass}{Density}[/tex]

(a) 432 g of table salt occupies 20.0 cm^3 of space

Here, we have:

[tex]Mass = 432g[/tex]

[tex]Volume = 20.0cm^3[/tex]

The above can be used to calculate Density as follows;

[tex]Density = \frac{Mass}{Volume}[/tex]

[tex]Density = \frac{432g}{20.0cm^3}[/tex]

[tex]Density = 21.6g/cm^3[/tex]

(b) 5.00 g of balsa wood, density of balsa wood : 0.16 g/cm^3

Here, we have:

[tex]Mass = 5.00g[/tex]

[tex]Density = 0.16g/cm^3[/tex]

This can be used to solve for Volume as follows:

[tex]Volume = \frac{Mass}{Density}[/tex]

[tex]Volume = \frac{5.00g}{0.16g/cm^3}[/tex]

[tex]Volume = 31.25cm^3[/tex]

(c) 32 cm^3 sample of gold density of 19.3 g/cm^3

Here, we have:

[tex]Volume = 32cm^3[/tex]

[tex]Density = 19.3g/cm^3[/tex]

This can be used to calculate Mass as follows:

[tex]Mass = Density * Volume[/tex]

[tex]Mass = 32cm^3 * 19.3g/cm^3[/tex]

[tex]Mass = 617.6g[/tex]

(d) 150 g of iron, density of Iron = 79.0 g/cm^3

Here, we have

[tex]Mass = 150g[/tex]

[tex]Density = 79.0g/cm^3[/tex]

This can be used to calculate volume as follows:

[tex]Volume = \frac{Mass}{Density}[/tex]

[tex]Volume = \frac{150g}{79.0g/cm^3}[/tex]

[tex]Volume = 1.90 cm^3[/tex] Approximated