Answer:
C
Step-by-step explanation:
Constant of proportionality = [tex] \frac{y}{x} [/tex]
Let's find out which if the boxes will give us 64 as constant of proportionality.
A. [tex] \frac{y}{x} = \frac{11}{2} = 5.5 [/tex] ≠ 64
B. [tex] \frac{y}{x} = \frac{5}{15} = \frac{1}{3} [/tex] ≠ 64
C. [tex] \frac{y}{x} = \frac{16}{\frac{1}{4}} = 16*\frac{4}{1} = 64 [/tex] ≠ 64
D. [tex] \frac{y}{x} = \frac{\frac{3}{7}}{3} = \frac{3}{7}*\frac{1}{3} = \frac{1}{7} [/tex] ≠ 64
E. [tex] \frac{y}{x} = \frac{2}{-10} = -\frac{1}{5} [/tex] ≠ 64
F. [tex] \frac{y}{x} = \frac{21}{6} = \frac{7}{2} [/tex] ≠ 64
G. [tex] \frac{y}{x} = \frac{4}{8} = \frac{1}{2} [/tex] ≠ 64
From the boxes given, box C is the only box that shows us a relationship where the constant of proportionality is 64.
