Answer: 0.500
Step-by-step explanation:
Given : A normal distribution has a mean[tex](\mu)[/tex] of 10 and a standard deviation[tex](\sigma)[/tex] of 1.
Let x be a random variable that represents numbers .
The probability of selecting a number that is at most 10 will be
[tex]P(x\leq10)=P(\dfrac{x-\mu}{\sigma}\leq\dfrac{10-10}{1})\\\\=P(z\leq0)=0.500[/tex]
As the area occupied by standard normal curve less than equal to 0 = 0.500
So, required probability = 0.500
