Answer:
6.004 Ω
Explanation:
For a Y- connected system given that :
Line voltage, [tex]$V_L = 208 \ V$[/tex]
Line current , [tex]$I_L=20\ A$[/tex]
and specified that [tex]$V_L \ and \ I_L$[/tex] are in phase.
Hence the impedance will be pure resistive.
For Y-system
[tex]$V_L = \sqrt3 V_{ph}$[/tex]
[tex]$V_{ph}$[/tex] = phase voltage
[tex]$V_{ph}$[/tex] [tex]$=\frac{V_L}{\sqrt3} = \frac{208}{\sqrt3}$[/tex]
= 120.08 V
Line current = Phase current
[tex]$I_L = I_{ph} = 20 \ A$[/tex]
Now, [tex]$z_{ph} = \frac{V_{ph}}{I_{ph}}=\frac{120.08}{20}$[/tex]
= 6.004 Ω
