A total of $44,000 is invested in two municipal bonds that pay 5.75% and 6.25% simple intrest. The investor wants an annual interest income of $2,680. What is the most that can be invested in the 5.75% bond?

Respuesta :

Answer:

$22333.33

Step-by-step explanation:

The total amount to be invested is $44,000.

Let x be the amount that can be invested in the 5.75% bond.

So, the annual simple interest for this amount is

[tex]I_1=x \times \frac{5.75}{100}=\frac{5.75x}{100}.[/tex]

The remaining amount that can be invested in the 6.25% bond is 44000-x.

The annual simple interest for this amount is

[tex]I_2=(44000-x) \times \frac{6.25}{100}=\frac{6.25x}{100}.[/tex]

As the investor wants an annual interest income of $2,680, so

[tex]I_1 + I_2 = 2,680[/tex]

[tex]\Rightarrow \frac{5.75x}{100} + \frac{6.25x}{100} = 2680[/tex]

[tex]\Rightarrow \frac{5.75x+6.25x}{100}= 2680[/tex]

[tex]\Rightarrow \frac{12x}{100}= 2680[/tex]

[tex]\Rightarrow x= \frac {2680\times100}{12}[/tex]

[tex]\Rightarrow x=22333.33[/tex]

Hence, the amount to be invested at a rate of 5.75% is $22333.33.