Answer:The sum of three numbers is 112.
a+b+c=112
The second number is 5 times the first.
b=5a
so a+5a+c=112
6a+c=112
The third number is 20 less than the second. What is the second number?
c=5a-20
6a+5a-20=112
11a-20+20=112+20
11a/11=132/11
a=12
Step-by-step explanation:
