Answer:
Fe2(SO4)3 has the greater iron content.
Explanation:
Hello!
In this case, considering the content of a specific element in a compound, we must take into account the subscript is has in the formula, for instance FeS has one iron atom, Fe2(SO4)3 has two iron atoms and FeCl2 has one iron atom; thus, by assuming one mole of each compound, we can compute the moles of iron there:
[tex]n_{Fe}^{FeS}=1molFeS*\frac{1molFe}{1molFeS}=1molFe \\\\n_{Fe}^{Fe_2(SO_4)_3}=1molFe_2(SO_4)_3*\frac{2molFe}{1molFe_2(SO_4)_3}=2molFe\\\\n_{Fe}^{FeCl_2}=1molFeCl_2*\frac{1molFe}{1molFeCl_2}=1molFe[/tex]
It means that Fe2(SO4)3 would have the greatest iron content.
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