6. Write an equation for the line that is parallel to the given line and that passes through the given point.
3
y =
X-9; (-8. -18)
3
11
y-Ž**ZH
y-
**-12
F
y = $x-12
y=-x+12
G
J

6 Write an equation for the line that is parallel to the given line and that passes through the given point 3 y X9 8 18 3 11 yŽZH y 12 F y x12 yx12 G J class=

Respuesta :

Answer:

The equation of new line is: [tex]\mathbf{y=\frac{3}{4}x-12}[/tex]

Option H is correct.

Step-by-step explanation:

We need to write an equation for the line that is parallel to the given line [tex]y=\frac{3}{4} x-9[/tex] and point (-8,-18)

The equation of required line will in in form [tex]y=mx+b[/tex] where m is slope and b is y-intercept.

We need to find slope m and b y-intercept for new line.

Finding slope:

When two lines are parallel, they have the same slope.

The slope of given line can be found by comparing the equation [tex]y=\frac{3}{4} x-9[/tex] with [tex]y=mx+b[/tex]

So, m = 3/4

The slope of new line will be: [tex]m=\frac{3}{4}[/tex]

Finding y-intercept:

Using slope m = 3/4 and point (-8,-18) we can find y-intercept

[tex]y=mx+b\\-18=\frac{3}{4}(-8)+b\\-18=-6+b\\b=-18+6\\b=-12[/tex]

So, y-intercept is b=-12

The equation of new line having m = 3/4 and b=-12 is:

[tex]y=mx+b\\y=\frac{3}{4}x-12[/tex]

So, the equation of new line is: [tex]\mathbf{y=\frac{3}{4}x-12}[/tex]

Option H is correct.