Given:
The total admission price for a group of 4 adults and 10 children is $57.
The total admission price for a group of 3 adults and 7 children is $41.
To find:
The admission prices for an adult and for a children.
Solution:
Let the price of an adult be x and price of children be y.
According to the question,
[tex]4x+10y=57[/tex] ...(i)
[tex]3x+7y=41[/tex] ...(ii)
Multiply equation (i) by 3.
[tex]12x+30y=171[/tex] ...(iii)
Multiply equation (i) by 4.
[tex]12x+28y=164[/tex] ...(iv)
Subtract (iv) from (iii).
[tex]12x+30y-12x-28y=171-164[/tex]
[tex]2y=7[/tex]
Divide both sides by 2.
[tex]y=3.5[/tex]
Put y=3.5 in (i).
[tex]4x+10(3.5)=57[/tex]
[tex]4x+35=57[/tex]
[tex]4x=57-35[/tex]
[tex]4x=22[/tex]
Divide both sides by 4.
[tex]x=5.5[/tex]
Therefore, the price for an adult is $5.5 and price for a child is $3.5.
