Answer:
A. [tex] PR = 80.6 yd [/tex]
B. Perimeter = 190.6 yd
Step-by-step explanation:
A. Distance between P(10, 50) and R(80, 10):
[tex] PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
[tex] PR = \sqrt{(80 - 10)^2 + (10 - 50)^2} [/tex]
[tex] PR = \sqrt{(70)^2 + (-40)^2} [/tex]
[tex] PR = \sqrt{4,900 + 1,600} [/tex]
[tex] PR = \sqrt{6,500} [/tex]
[tex] PR = 80.6 yd [/tex] (nearest tenth)
B. Distance around the park = Perimeter = PR + PQ + QR
PR = 80.6 yd
PQ = |50 - 10| = 40 yd
QR = |80 - 10| = 70 yd
Perimeter = 80.6 + 40 + 70
Perimeter = 190.6 yd
