Answer:
[tex]a=114\ m/s^2[/tex]
Explanation:
Given that,
Mass of an object, m = 3.68 kg
It is whirled in a horizontal circle of radius 881 cm or 8.81 m
The object completes 10.8 revolutions every 18.8
s.
We need to find the centripetal acceleration of the object. It is given by the formula as follows :
[tex]a=\omega^2 r[/tex] ...(1)
Where [tex]\omega[/tex] is angular velocity
10.8 revolutions = 67.85 rad
[tex]\omega=\dfrac{67.85\ rad}{18.8\ s}\\\\=3.6\ rad/s[/tex]
Put values in equation (1)
[tex]a=3.6^2\times 8.81\\\\a=114\ m/s^2[/tex]
So, the centripetal acceleration of the object is [tex]114\ m/s^2[/tex].
