MCU2003
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An acute angle θ is in a right triangle with sin θ = eight ninths. What is the value of cot θ? nine divided by the square root of seventeen square root of seventeen divided by eight eight divided by the square root of seventeen square root of seventeen divided by nine

Respuesta :

Answer:

[tex]\frac{\sqrt{17} }{9}[/tex]

Step-by-step explanation:

a^2 +b^2 =c^2 Use pythagorean theorem

8^2 +b^2 =9^2 Substitute in your known values

b=[tex]\sqrt{17} , -\sqrt{17}[/tex]

b=[tex]\sqrt{17}[/tex] A triangle leg cannot be a negative length

[tex]\frac{\sqrt{17} }{9}[/tex] Find cosine of angle theta.

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