If the point (8,-5) is 6 units above the point P(x, y) and 3 units to the right of it, then what are the coordinates of
the point P(x, y)?

We know that (8, -5) is 6 units above and 3 units to the right of point P. Knowing this, let's work backwards by starting from (8,-5) and counting 6 units down and 3 units to the left on the graph.

If you counted correctly, this should place you at the (5, -11). (You can also check your work by counting 6 units up and 3 units to the right from (5, -11) and seeing if you end up at (8, -5).)

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If the point (8,-5) is 6 units above the point P(x, y) and 3 units to the right of it, then what are the coordinates of the point P(x, y)?

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If the point (8,-5) is 6 units above the point P(x, y) and 3 units to the right of it, then what are the coordinates of
the point P(x, y)?