The new pressure will be doubled
Given
A sample of ozone (O₃) at x K and 12.5 Pa. (T₁= x K, P₁=12.5 Pa)
the temperature is doubled to 2x K (T₂=2x)
Required
the new pressure
Solution
Gay Lussac's Law
When the volume is not changed, the gas pressure is proportional to its absolute temperature
[tex]\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]
Input the value :
[tex]\tt \dfrac{12.5}{x}=\dfrac{P_2}{2x}\\\\P_2=\dfrac{12.5\times 2x}{x}[/tex]