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Randolph is creating parallelogram WXYZ so that XY has an equation of y = 2 over 3x −5. Segment WZ must pass through the point (−6, −1). Which of the following is the equation for WZ?
A. y − (−6) = 2 over 3(x − (−1))
B. y − (−1) = 2 over 3(x − (−6))
C. y − (−6) = 3 over 2(x − (−1))
D. y − (−1) = 3 over 2(x − (−6))

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Answer:

The correct answer is y - (-1)= 2/3(x - (-6))

Step-by-step explanation:

I know there was some confusion as to weather this answer was correct. But i an tell you that i am on FLVS and this was the correct answer to this problem.

Hope you found this helpful :)

To solve the problem we will use the property of parallelogram.

What is a Parallelogram?

A parallelogram is a quadrilateral whose opposite sides are parallel to each other and equal in size.

The equation of the line WZ is [tex]y-(-1) = \dfrac{2}{3}[x -(-6)][/tex].

Given to us

  • Randolph is creating parallelogram WXYZ,
  • XY has an equation of y = 2 over 3x −5
  • WZ must pass through the point (−6, −1)

Slope of the Line WZ

As we know for a parallelogram opposite sides must be parallel, therefore, line XY and WZ should be parallel to form a quadrilateral.

Thus, the slope of both the lines will be equal to each other.

Writing the equation of line for WZ

[tex]y = mx+c\\y = \dfrac{2}{3}x + c[/tex]

Value of Constant for equation of line WZ

As the line WZ passes through the point (-6, -1), therefore, substituting the given point to find the value of constant,

[tex]-1 = \dfrac{2}{3}(-6) + c\\\\-1 = 2(-2) + c\\\\-1 = -4 +c\\\\-1+4 =c\\\\c = 3[/tex]

Equation of the line WZ

[tex]y = \dfrac{2}{3}x + 3[/tex]

Adding +1, -1 on the right side of the equation,

[tex]y = \dfrac{2}{3}x + 3-1+1\\\\y+1=\dfrac{2}{3}x + 3+1\\\\y+1=\dfrac{2}{3}x + 4[/tex]

Taking [tex]\frac{2}{3}[/tex] as common,

[tex]y-(-1) = \dfrac{2}{3}(x +6)\\\\y-(-1) = \dfrac{2}{3}[x -(-6)][/tex]

Hence, the equation of the line WZ is [tex]y-(-1) = \dfrac{2}{3}[x -(-6)][/tex].

Learn more about Parallelogram:

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