The increased volume will be "706 L".
According to the question,
Pressure,
- Initial, [tex]P_1 = 3 \ atm[/tex]
- Final, [tex]P_2 = 1 \ atm[/tex]
Temperature,
- Initial, [tex]T_1 = 17^{\circ} C[/tex] or, [tex]290 \ K[/tex]
- Final, [tex]T_2 = 273 \ K[/tex]
Volume,
- Initial, [tex]V_1 = 250 \ L[/tex]
- Final, [tex]V_2 = \ ?[/tex]
By using the Boyl's and Charl's combination law, we get
→ [tex]\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}[/tex]
or,
→ [tex]V_2 = \frac{P_1 V_1 T_2}{T_1 P_2}[/tex]
By putting the values, we get
→ [tex]= \frac{3\times 250\times 273}{290\times 1}[/tex]
→ [tex]= 706 \ L[/tex]
Thus the aforementioned answer is right.
Learn more about pressure here:
https://brainly.com/question/19156022
