Answer:
Volume of oxygen produced = 403 L
Explanation:
Given data:
Number of moles of NaClO₃ = 12.0 mol
Volume of oxygen produced = ?
Temperature = 273 K
Pressure = 1 atm
Solution:
Chemical equation:
2NaClO₃ → 2NaCl + 3O₂
Now we will compare the moles of oxygen and NaClO₃ .
NaClO₃ : O₂
2 ; 3
12.0 : 3/2×12.0 = 18.0 mol
Volume of oxygen produced:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1 atm × V = 18.0 mol × 0.0821 atm.L/mol.K × 273 K
V = 403 L .atm / 1 atm
V = 403 L
