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A stone is dropped from the height of 121m and reaches to the earth in 10 sec with an acceleration of 20m/s square find the initial velocity of the stone​

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lucky75

question:-

  • A stone is dropped from the height of 121m and reaches to the earth in 10 sec with an acceleration of 20m/s square find the initial velocity of the stone

Given :-

  • Height = 121 m

  • Time = 10 sec

  • Acceleration = 20 m/s²

To Find :-

  • Initial Velocity

Solution :-

As we know that,

[tex]\boxed{ \sf \: {v}^{2} - {u}^{2} = 2as }[/tex]

  • V = Final Velocity
  • U = Initial Velocity
  • A = Acceleration
  • S = Distance

According to the question,

0² - u² = 2(20)(121)

0 - u² = 4840

-u² = 4840

-u = √4840

u = -69.5 m/s

Answer:-

The initial velocity of the stone is -69.5 m/S.

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