Answer:
Expanding form
[tex]\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}[/tex]
[tex]1-\frac{9}{7}n[/tex]
Step-by-step explanation:
We are given that [tex]\frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})[/tex]
We have to expand the terms and combine like terms
[tex]\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}[/tex]
Expanding form
[tex]\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}[/tex]
In the given expression like terms are [tex]\frac{1}{7}[/tex]and [tex]\frac{6}{7}[/tex]
[tex]\frac{1}{7}+\frac{6}{7}-\frac{9}{7}n[/tex]
[tex]\frac{1+6}{7}-\frac{9}{7}n[/tex]
[tex]\frac{7}{7}-\frac{9}{7}n[/tex]
[tex]1-\frac{9}{7}n[/tex]
