The magnitude and direction of points M(-3, -2) and N(4, 0) is 7.28 units and 74.1 degrees
How to determine the magnitude and direction?
We have:
M(-3, -2) and N(4, 0)
Calculate the magnitude using
[tex]MN =\sqrt{(x_2 -x_1)^2 +(y_2 -y_1)^2[/tex]
This gives
[tex]MN =\sqrt{(4 + 3)^2 +(0 + 2)^2[/tex]
Evaluate
MN = 7.28
The direction is calculated as:
[tex]\theta = 90 - \tan^{-1}(\frac{y_2 - y_1}{x_2 -x_1})[/tex]
This gives
[tex]\theta = 90 -\tan^{-1}(\frac{0+2}{4+3})[/tex]
[tex]\theta =90 - \tan^{-1}(\frac27)[/tex]
Take the arc tan
[tex]\theta = 90 - 15.9\°[/tex]
Evaluate
[tex]\theta = 74.1\°[/tex]
Hence, the magnitude and direction of points M(-3, -2) and N(4, 0) is 7.28 units and 74.1 degrees
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