Respuesta :

Answer:

yes , keiko is correct.

sin^(-1)x = -sin^1

Answer:

Keiko is wrong

Step-by-step explanation:

Keiko is incorrect

When n is positive, 1^n will always be 1

but........ (-1)^n will not always be -1

This is because there are parenthesis around -1

So n is even, then it will be 1 not -1

For example, n = 4

You will do -1 * -1 * -1 * -1 which is 1 not -1

but if n = 3

You will do -1 * -1 * -1 which is -1

Therefore, the second statement is incorrect resulting in Keiko being wrong