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Balance the following equation. What is the coefficient for hydrogen fluoride?
SiO2 + HF →→SiF4 +H2O
A) 3
B) 2
C) 1
D) 4

Respuesta :

arulmalu

Answer:

ans .4

Explanation:

SiO2 +HF ⇒ SiF4 +H2O

reactant side                          product side

Si = 1                                    Si = 1      its balanced

O = 2                    O = 1    (× WITH 2 ) we got O =2 And H = 4

H = 1                                     H = 2  NOW H =4

F= 1   (×4)                                   F   = 4

now we get SiO2 +4 HF ⇒SiF4 +2 H2O

After multiply with number again check it. Si = 1, O = 2 ,H=4 ,F=4

mahima6824soni

The coefficient for hydrogen fluoride is 4.

The correct option is D, 4.

What is hydrogen fluoride?

It is a chemical compound with chemical formula HF.

It is a colorless gas or liquid.

[tex]\rm SiO_2 +HF = SiF4 +H_2O[/tex]

We will calculate the moles of compounds on both side

Reactant side                          Product side

Si = 1                                    Si = 1      its balanced

O = 2                                    O = 1   (multiply it by 2)

                                             o =2 and H = 4

H = 1                                     H = 2  NOW H =4

F= 1   (×4)                                   F   = 4

The balanced equation is

[tex]\rm SiO_2 +4 HF =SiF_4 +2 H_2O[/tex]

Thus, The coefficient for hydrogen fluoride is 4.(D).

Learn more about HF, here:

https://brainly.com/question/7218888

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