Answer:
Tn = 3n-1
T6 = 17
Step-by-step explanation:
Given the arithmetic sequence;
2, 5...
first term a = 2
Common difference d = 5-2 = 3
nth term of an AP is expressed as Tn = a + (n-1)d
Tn = 2 + (n-1)(3)
Tn = 2 + 3n-3
Tn = 3n-1
Get the 6th term
T6 = 3(6)-1
T6 = 18-1
T6 = 17
Hence the 6th term of the sequence is 17